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If you multiply four consecutive integers and add one, you get a perfect square. \begin{align*} a(a+1)(a+2)(a+3) + 1 &= a^4 + 6a^3 + 11a^2 + 6a + 1 \\ &= (a^2+3a+1)^2 \end{align*}
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Thu, 14 Jan 2021 10:41 GMT