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$2^{-\log_8(125)} = (8^{\frac{1}{3}})^{- \log_8(125)} = (8^{-\log_8(125)})^{\frac{1}{3}} = (\frac{1}{8^{\log_8(125)}})^{\frac{1}{3}} = (\frac{1}{125})^{\frac{1}{3}} = \frac{1}{5}$
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Mon, 04 Jan 2021 12:47 GMT