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Prove $P(A\cap B)=P(A)\cap P(B)$ Let $x\in P(A\cap B)$ $x\in P(c)\rightarrow x\subseteq c$ $x\subseteq P(A)\cap P(B)$ $x\subseteq P(A)\wedge P(B)$ $x\in P(A)\wedge P(B)$
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Fri, 04 Oct 2019 02:02 GMT