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$\large N(n)=\begin{cases} x_0+\frac{2\pi}{b} \frac{n-2}{2}, & n \text{ gerade} \\ \pi-x_0+\frac{2\pi}{b}\frac{n-1}{2}, & n\text{ ungerade} \end{cases}$
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Mon, 23 Sep 2019 15:22 GMT