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$|\pi\pi, I =2, I_3 = 0> = \frac{1}{\sqrt{6}}(\,2|\pi^0\pi^0> +\;|\pi^+\pi^-> +\;|\pi^-\pi^+>)$ $|\pi\pi, I =1, I_3 = -1> = \frac{1}{\sqrt{2}}(\;|\pi^0\pi^-> -\;|\pi^-\pi^0>)$ $|\pi\pi, I =0, I_3 = 0> = \frac{1}{\sqrt{4}}(+\;|\pi^-\pi^+>) +\;|\pi^+\pi^->)-\;|\pi^0\pi^0>$
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Mon, 15 Jan 2018 04:26 GMT