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$A(f) = \frac{\frac{1}{k}}{1+\frac{1}{k\cdot A_D}} = \frac{\frac{1}{k}}{1+\frac{1}{k\cdot A_{D0}}\cdot\left(1+j\cdot \frac{f}{f_{gD}}\right)}$ Und wegen $\frac{1}{|k|\cdot A_{D0}} << 1$ ergibt sich: $A(f) = \frac{\frac{1}{k}}{1+j\cdot \frac{f}{A_{D0}\cdot k \cdot f_{gD}}}$
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Sun, 07 Jan 2018 11:58 GMT