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$$-mg -\beta v = m \frac{dv}{dt}$$ $$m \frac{dv}{dt} +\beta v +mg = 0 $$ Divide by m: $$\frac{dv}{dt} +\frac{\beta}{m}v +g = 0 $$ let $k^2 = \frac {\beta}{m}$ $$\frac{dv}{dt} +k^2v +g = 0 $$
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Sat, 18 Nov 2017 17:24 GMT