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$625y^4 - 1 = 0$ $y = \pm\sqrt[4]{-1/625}$ $y = \pm\sqrt{\pm\sqrt{-1/625}}$ $y_{1,2} = \pm\sqrt{\pm\frac{i}{25}}$ $y_{1} = \pm\frac{\pm\frac{1 + i}{\sqrt{2}}}{5} = \pm\frac{1 + i}{5\sqrt{2}} = \pm(\frac{1}{5\sqrt{2}} + \frac{i}{5\sqrt{2}})$ $y_2 = \pm\sqrt{-1*\frac{i}{25}} = \pm i \frac{\pm\frac{1 + i}{\sqrt{2}}}{5} = \pm\frac{\pm\frac{i - 1}{\sqrt{2}}}{5} = \pm(\frac{i}{5\sqrt{2}} - \frac{1}{5\sqrt{2}})$
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Sun, 29 Oct 2017 22:54 GMT