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${\large{\dfrac{n+2}{n-1}=\dfrac{n\cdot1+{\color{Blue}{n\cdot\dfrac{1}{n}}}\cdot2}{n\cdot 1-{\color{Blue}{n\cdot\dfrac{1}{n}}}\cdot1}=\dfrac{n\cdot(1+\dfrac{1}{n}\cdot2)}{n\cdot(1-\dfrac{1}{n}\cdot1)}=\dfrac{n\cdot(1+\dfrac{2}{n})}{n\cdot(1-\dfrac{1}{n})}}}$
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Fri, 06 Oct 2017 14:37 GMT