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$x=a(1+2\cos t)$ $y=a(\tan t+ 2\sin t)=a \tan t (1+\cos t)=\tan t x(t)$ Самопересечение $a(1+2\cos t_1)=a(1+2\cos t_2)=0$ $\cos t_1=\cos t_2=-1/2$ $S=\int\limits_{\pi}^{2\pi/3} y(t) x'(t) dt= 2a^2 \int\limits_{2\pi/3}^{\pi} \tan t (1+\cos t)\sin t dt $
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Sat, 02 May 2020 08:56 GMT