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\[ \frac{x-1}{x^2(x+1)}\hspace{2mm}=\hspace{2mm} \frac{A}{x}+\frac{B}{x^2}+\frac{C}{x+1} \] So then: \[ x-1= Ax(x-1)+B(x+1)+Cx^2 \]
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Sun, 08 Mar 2020 18:05 GMT