MathB.in
New
Demo
Tutorial
About
$\frac{\alpha}{1-\alpha}\lambda(\theta)\log \sum_x (\lambda(\theta)p_\theta(x))(\lambda(\theta')q_\theta'(x))^{\alpha-1} - \frac{\lambda(\theta)}{1-\alpha}\log \sum_x (\lambda(\theta)p_\theta(x))^\alpha$
ERROR: JavaScript must be enabled to render input!
Mon, 23 Dec 2019 16:06 GMT