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$\frac{2(\sqrt{2} + \sqrt{6})}{3(\sqrt{2} + \sqrt{3})} = \frac{2\sqrt{2}(1+\sqrt{3})}{3(\sqrt{2} + \sqrt{3})}$ $=\frac{2}{3}\sqrt{2}\frac{(1+\sqrt{3})(\sqrt{2}-\sqrt{3})}{2-3}$ $=-\frac{2}{3}(2 + 2\sqrt{3} - 3\sqrt{2} - \sqrt{6})$
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Sat, 15 Jun 2019 12:37 GMT